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cos3x=sin2x...

cos3x=sin2x

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Find x cos3x+sin(2x-(7 pi)/(6))=-2

int(3cos3x-2sin2x)/(cos2x+sin3x)dx

cos^3x.sin2x=sum_(m=1)^n(a_m)sin mx is an identity in x.

If cos3x+sin(2x-(7pi)/6)=-2 , then show that x is of the form π / 3(6m+1) .

If cos3x+sin(2x-(7pi)/6)=-2 , then show that x is of the form π / 3(6n+1) .

cos3x-cos2x=sin3x

cos3x + sin(2x- (7pi)/6)=-2

Solve the following equation : cos 3x = sin 2x .