Four moles of an ideal gas is initially in state `A` having pressure ` 2 xx 10^(5) N//m^(2)` and temperature ` 200 K` . Keeping the pressure constant the gas is taken to state `B` at temperature of `400K`. The gas is then taken to a state `C` in such a way that its temperature increases and volume decreases. Also from `B` to `C` , the magnitude of `dT//dV` increases. The volume of gas at state `C` is eqaul to its volume at statem `A`. Now gas is taken to initial state `A` keeping volume constant. A total `1000 J` of heat is withdrawn from the sample of the cyclic process . Take `R=8.3 J// K// mol`. The volume of gas at state `C` is

Four moles of an ideal gas is initially in state A having pressure 2 xx 10^(5) N//m^(2) and temperature 200 K . Keeping the pressure constant the gas is taken to state B at temperature of 400K . The gas is then taken to a state C in such a way that its temperature increases and volume decreases. Also from B to C , the magnitude of dT//dV increases. The volume of gas at state C is eqaul to its volume at statem A . Now gas is taken to initial state A keeping volume constant. A total 1000 J of heat is withdrawn from the sample of the cyclic process . Take R=8.3 J// K// mol . The work done in path B to C is

Four moles of an ideal gas is initially in state A having pressure 2 xx 10^(5) N//m^(2) and temperature 200 K . Keeping the pressure constant the gas is taken to state B at temperature of 400K . The gas is then taken to a state C in such a way that its temperature increases and volume decreases. Also from B to C , the magnitude of dT//dV increases. The volume of gas at state C is eqaul to its volume at statem A . Now gas is taken to initial state A keeping volume constant. A total 1000 J of heat is withdrawn from the sample of the cyclic process . Take R=8.3 J// K// mol . Which graph between temperature T and volume V for the cyclic process is correct.

Four moles of an ideal gas is initially in a state A having pressure 2xx10^(5)N//m^(2) and temperature 200 K . Keeping pressure constant the gas is taken to state B at temperature of 400K. The gas is then taken to a state C in such a way that its temperature increases and volume decreases. Also from B to C, the magnitude of (dT)/(dV) increases. The volume of gas at state C is eaual to its volume at state A. Now gas is taken is initial state A keeping volume constant. A total of 1000 J heat is rejected from the sample in the cyclic process. Take R=8.3J//K//mol . The work done by the gas along path B to C is

Four moles of an ideal gas is initially in a state A having pressure 2xx10^(5)N//m^(2) and temperature 200 K . Keeping pressure constant the gas is taken to state B at temperature of 400K. The gas is then taken to a state C in such a way that its temperature increases and volume decreases. Also from B to C, the magnitude of (dT)/(dV) increases. The volume of gas at state C is eaual to its volume at state A. Now gas is taken is initial state A keeping volume constant. A total of 1000 J heat is rejected from the sample in the cyclic process. Take R=8.3J//K//mol . The work done by the gas along path B to C is

Four moles of an ideal gas is initially in a state A having pressure 2xx10^(5)N//m^(2) and temperature 200 K . Keeping pressure constant the gas is taken to state B at temperature of 400K. The gas is then taken to a state C in such a way that its temperature increases and volume decreases. Also from B to C, the magnitude of (dT)/(dV) increases. The volume of gas at state C is eaual to its volume at state A. Now gas is taken is initial state A keeping volume constant. A total of 1000 J heat is rejected from the sample in the cyclic process. Take R=8.3J//K//mol . Which graph between temperture T and volume V for the cyclic process is correct.

Four moles of an ideal gas is initially in a state A having pressure 2xx10^(5)N//m^(2) and temperature 200 K . Keeping pressure constant the gas is taken to state B at temperature of 400K. The gas is then taken to a state C in such a way that its temperature increases and volume decreases. Also from B to C, the magnitude of (dT)/(dV) increases. The volume of gas at state C is eaual to its volume at state A. Now gas is taken is initial state A keeping volume constant. A total of 1000 J heat is rejected from the sample in the cyclic process. Take R=8.3J//K//mol . Which graph between temperture T and volume V for the cyclic process is correct.

Two moles of an idea gas is initially in state A having pressure 1.01xx10^(5)N//m^(2) and temperature 3O0k keeping pressure constant the gas is taken to state B temperature at B is 500K the gas is then taken to state C in such a way that its temperature increases and volume decreases also from B To c the magnitude of (dT)/(dV) increases the volume of gas at C is equal to volume of gas at A now the gas is taken to initial state A keeping volume constant A total of 1200 J of heat is with drawn from the sample in the cyclic process the T-V graph for the cyclic process and work done in path B to C are respectively (take R=8.3J//k//mol)

Can the temperature of a gas increased keeping its pressure and volume constant ?

Can the temperature of a gas increased keeping its pressure and volume constant ?

The following graphs are plotted for an ideal gas taken from state A to state B and then to state C, maintaining volume constant.