Two cells of emf 4 V and 8 V are connected to two resistor `4Omega` and `6Omega` as shown. If 8 V cell is short circuited. Then current through resistance `4Omega` and `6Omega`

A cell of e.m.f. 3 V and internal resistance 4 Omega is connected to two resistances of 10 Omega and 24 Omega joined in parallel. Find the current through each resistance using Kirchhoff's laws

A battery of e.m.f. 15 V and internal resistance 3 Omega is connected to two resistors 3 Omega and 6 Omega connected in parallel. Find : the current through the battery,

Two cells of 6 V and 4 V having internal resistance of 3 Omega and 2 Omega respectively are connected in parallel so as to send a current through an external resistance 8 Omega in the same direction. Find the current through the cells and the current through the external resistance.

A battery of e.m.f. 15 V and internal resistance 3 Omega is connected to two resistors 3 Omega and 6 Omega connected in parallel. Find : the current in 6 Omega resistor.

A battery of e.m.f. 15 V and internal resistance 3 Omega is connected to two resistors 3 Omega and 6 Omega connected in parallel. Find : the current in 3 Omega resistor,

Two cells having emf's of 10 V and 8 V, respectively, are connected in series with a resistance of 24Omega In the external circuit. Their internal resistances are 2Omega// V (proportional to their emf's). Find the current in the circuit

Two cells having emf's of 10 V and 8 V, respectively, are connected in series with a resistance of 24Omega In the external circuit. Their internal resistances are 2Omega// V (proportional to their emf's). Find the current in the circuit

Three resistors 8 Omega , 12 Omega and 6 Omega are connected to a 12 V battery as shown in Fig. below. the current through the 8 Omega resistor,

Three resistors 8 Omega , 12 Omega and 6 Omega are connected to a 12 V battery as shown in Fig. below. the current through the 6 Omega resistor.

4 cells each of emf 2 V and internal resistance of 1Omega are connected in parallel to a load resistor of 2Omega . Then the current through the load resistor is