[" 31.If "k=tan25^(@)" then "(k-1)/(k+1)+(k+1)/(k-1)=],[" psec "130^(@)" Then "p=]

If (k+(1)/(k))^(2)=16 , then k^(2)+(1)/(k^(2))=

sum_(k =1)^(n) k(1 + 1/n)^(k -1) =

Given 5P(4, k) = 6 P(5, k-1), k ge 1 . Then

If (k-1),(2k+1),(6k+3) are in GP then k=?

If A+B+C=pi&sin(A+(C)/(2))=k(sin C)/(2), then (tan A)/(2)(tan B)/(2)= a.(k-1)/(k+1) b.(k+1)/(k-1) c.(k)/(k+1) d.(k+1)/(k)

The points (k-1, k+2),(k , k+1),(k+1, k) are collinear for

If "tan"^(-1)x+"tan"^(-1)"1"/x={(pi//k,if", "xge0),(-pi//k,if", "xlt0):} , then the value of K is

If (sin x)/(a)=(cos x)/(b_(k))=(tan x)/(c)=k, then bc+(1)/(ck)+(ak)/(1+bk) is equal to k(a+(1)/(a)) (b) 1/k(a+(1)/(a))(1)/(k^(2))(d)(a)/(k)