What is the oxidation state of Kin `KO_2 and why is this compound paramagnetic?

Explanation

The superoxide ion is represented as `O_2^(-)` It has one unit of negative charge. Since the compound is nutral, therefore, the oxidation state of K is +l. The structure of `O_2^(-)` is `^(Θ):underset(* *)overset(* *)O-underset(* *)overset(* *)O:`.
Since it has one unpaired electron in `pi_(2p)^(**)MO`, therefore, the compound is paramagnetic.