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Lithium forms monoxide while sodium form...

Lithium forms monoxide while sodium forms peroxide in the presence of excess oxygen-why?

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Larger cations can be stabilised by larger anions because if both the ions are comparable in size, the coordination number will be high and this gives rise to a high lattice enthalpy. Lithium ion, `Li^(+)` as well as oxide ion, `O^(2-)` , have small ionic radii and high charge densities. Hence these small ions combine together and form a very stable lattice of lithium monoxide `(Li_2O)`. Similarly, formation of sodium peroxide `(Na_2O_2)` can be explained on the basis of the stable lattice formed by the packing ofr elatively large `Na^(+)` ion and peroxide ion `O_2^(2-)`.
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Lithium forms monoxide, sodium gives peroxide while the rest of the alkali metals form superoxide. Explain

Alkali metals on combustion in excess of air form different type of oxides depending on the size of metal cations e.g . lithium forms mainly the oxide Li_2O , sodium forms peroxide and some super oxides NaO_2 and potassium, Rubidium and caesium form the superoxides, MO_2 . The stability of peroxide and superoxide increases, as the size of the metal cation increases because of the stabilisation of larger anion by larger cations through lattice energy effect. These oxides are easily hydrolysed by water. The oxides and the peroxides are colourless when pure, but the superoxides are yellow or orange in colour. Peroxide and superoxide of sodium and potassium are widely used as oxidising agent and as air purifier in space capsules, submarines and breathing mask. When sodium reacts with excess of oxygen at 350^@ C , the oxidation number of oxygen per atom changes from:

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