Give an example of a disproporrtionation reaction ? Calculate the volume of 0.2225(M)`KMnO_(4)`solution that can completely react with 45mL. Of a 0.125(M) `FeSO_(4)`solution in an acid meduim .

Explanation

Second part:
Oxidation reaction : `[Fe^(2+)(aq)toFe^(3+)(aq)+e]xx5`
Reduction reaction : `MnO_(4)-(aq)+8H^(+)(aq)Mn^(2+)+(aq)+4H_(2)O(l)xx1`
Net reaction `5Fe^(3+)(aq)+MnO_(4)-(aq)+8H^(+)(aq)5Fe^(3+)(aq)+Mn^(2+)(aq)+4H_(2)O(l)`
`therefore "5 mol "of FeSO_(4)-=1 "mol of" MnO_(4)^(-)`
"or, 1000mL "of 5 M `FeSO_(4)`=1000"mL of" 1 "M `KMnO_(4)`
or ,"1 mL of "5 M `FeSO_(4)`=1mL "of 1M `KMnO_(4)`
Or", 45,mL of "1M `FeSO_(4)=(1)/(5)`mL of 1M `KMnO_(4)`
or," 45mL of 0.125M"`FeSO_(4)=45xx0.125xx(1)/(3)mL`"of 1M"
`KMnO_(4)=(9xx0.125)/(0.225)`mL" of 0.225M" `KMnO_(4)`
="5mL of 0.225M" `KMnO_(4)`
`therefore`"The volume of" `KMnO_(4)`requred =5mL.