Home
Class 11
CHEMISTRY
Determine the equivalent masses of the f...

Determine the equivalent masses of the following underline compounds by both oxidantion number and electrons methods:
underline`(SO_(2))+2H_(2)OtoH_(2)SO_(4)`

Text Solution

Verified by Experts

Oxidation number method: `SO_(2)`
=`("Molecuar mass "of SO_(2))/(2)=(64)/(2)=32`
Electronic method `SO_(2)+2H_(2)Oto4H^(+)+SO_(4)^(2)+2e`
Number of electron lost by a molecule of `SO_(2)` for its oxidation =2
`therefore`Equivalent mass of `SO_(2)=(64)/(2)=32`
Promotional Banner

Topper's Solved these Questions

  • REDOX REACTIONS

    CHHAYA PUBLICATION|Exercise QUESTION- ANSWER ZONE FOR BOARD EXAMINATION (VERY SHOT ANSWER TYPE)|44 Videos
  • REDOX REACTIONS

    CHHAYA PUBLICATION|Exercise SOLVED WBCHSE SCANNNER|20 Videos
  • CLASSIFICATION OF ELEMENTS & PERIODICITY IN PROPERTIES

    CHHAYA PUBLICATION|Exercise PRACTICE SET|12 Videos
  • s-BLOCK ELEMENTS

    CHHAYA PUBLICATION|Exercise PRACTICE SET|16 Videos

Similar Questions

Explore conceptually related problems

Determine the equivalent masses of the following underline compounds by both oxidation number and electrons methods: underline (HNO_(3))toNO_(2)+H_(2)O

Determine the equivalent masses of the following underline compounds by both oxidation number and electrons methods: underline (HNO_(3))+3H^(+)toNO+2H_(2)O

Determine the equivalent masses of the following underline compounds by both oxidantion number and electrons methods: (MnO_(2))+4H^(+)toMn^(2+)+2H_(2)O

Determine the equivalent masses of the following underline compounds by both oxidantion number and electrons methods: underline (KMnO_(4))underline+(FeSO_(4))+H_(2)SO_(4)K_(2)SO_(4)+MnSO_(4)+Fe_(2)(SO_(4))+H_(2)O

Determine the equlavent weights of the underlined compounds in the following two reactions: FeSO_(4)+underline (KMnO_(4))+H_(2)SO_(4)toK_(2)SO_(4)+MnSO_(4)+Fe_(2)(SO_(4))_(3)+H_(2)O

Determine the pH of the following: 0.01(M)H_2SO_4

Determine the equlavent weights of the underlined compounds in the following two reactions: underline (MnO_(2))+HCItoMnCI_(2)+CI_(2)+H_(2)O[K=39,Mn=55,O=16]

Balance the reaction by ion-electrons mehod : MnO_(4)^(-)SO_(2)^(2-)+H_(2)OtoMn^(2+)H^(+)SO_(4)^(2-)

Determine the oxidation number of S in H_2SO_4 .

Balance the equation by ion-electron method : MnO_(4)^(-) + SO_(2) + H_(2)O to Mn^(2+) + SO_(4)^(2-) + H^(+)