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Determine the equivalent masses of the f...

Determine the equivalent masses of the following underline compounds by both oxidantion number and electrons methods:
`(MnO_(2))+4H^(+)toMn^(2+)+2H_(2)O`

Text Solution

Verified by Experts

Oxidation number method :
`Moverset(+4)nO_(2)+4H^(+)to overset(+2)Mn^(2+)+2H_(2)O`In this reaction the oxidation number of decrease from +4 to +2 .So the change ub oxidation number per molecular of `MNO_(2)`=4-2=2unit.
`therefore`Equivalent mass of `MnO_(2)` Electronic method: `MnO_(2)+4H^(+)+2etoMn^(2+)+2H_(2)O`
The number of electrons invoved in the reduction of 1 molecule of `MnO_(2)=2`
t`herefore`Equivalent mass of of `MnO_(2)`
=`("Molecular mass "of MNO_(2))/(1)=(87)/(2)=43.5`
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