Balance the following equation with the help of oxidation number method.
`MnO_(2)+HCl to Mn^(2+)+Cl_(2)+H_(2)O`

Explanation

Oxidation half-reaction : `2 Cl^(-)toCI_(2)+2e`
Reduction half -reaction : underline (`MnO_(2)+4H^(+)+2etoMn^(2+)+2H_(2)O`) `therefor e`Net reaction : `MnO_(2)+4H^(+)+2CI^(-)toMn^(2+)+CI_(2)+2H_(2)O`
or `MnO_(2)+4H^(+)+4CI^(-)toMn^(2+)+2CI^(-)+CI_(2)+2H_(2)O`
therefore the balanced chemical equation is-
`MnO_(2)+4HCItoMnCI_(2)+CI_(2)+2H_(2)O`