Light of wavelength `lambda` in air enters a medium of refractive index `mu`. Two points in this medium, lying along the path of this light, are at a distance of x apartThe phase difference between these point is

Light of wavelength lambda in air enters a medium of refractive index mu . Two points in this medium, lying along the path of this light, are at a distance x apart. The phase difference between these points is :

Light of wavelength lambda_(0) in air enters a medium of refractive index n. If two points A and B in this medium lie along the path of this light at a distance x, then phase difference phi_(0) between these two point is

Light of wavelength lambda_(0) in air enters a medium of refractive index n. If two points A and B in this medium lie along the path of this light at a distance x, then phase difference phi_(0) between these two point is

Light of wavelength 6000 Å in air enters a medium of refractive index 1.5. What will be its wavelength in the medium ?

A light wave enters from air into a medium of refractive index 1.5. The speed of light in the medium will be

A light of wavelength 6000 in air enters a medium of refractive index 1.5 . Inside the medium , its frequency is v and it wavelength is lambda .

Find the speed of light of wavelength lambda=600nm (in air) in a medium of refractive index 5//3 and also wavelength of this light in medium.