" tide travels in a circular path of radius "0.45" min a magnetic field "B=1.2" Wb/m "^(2)" with a speed of "26times10^(7)" m/s.The period of "

An alpha particle travels in a circular path of radius 0.45 m in a magnetic field B = 1.2 Wb//m^(2) with a speed of 2.6xx10^(7) m//sec . The alpha particle is

A particle moves in a circular path of radius 0.5 m with a linear speed of 2 ms^(-1) ,its angular speed is

An electron travels on a circular path of radius 10 m in a magnetic field of 2 xx 10^(–3) T. Calculate the speed of electron. What is the potential difference through which it must be accelerated to acquire this speed?

An electron is moving with a velocity of 10^(7) ms^(-1) on a circular path of radius 0.57 cm in a magnetic field of 10^(-2) Wbm^(-2) . Find the value of e//m for the electron.

An alpha -particle moves in a circular path of radius 0.83 cm in the presence of a magnetic field of 0.25 Wb//m^(2) . What is the de Broglie wavelength associated with the particle?

An a-particle moves along a circular path of radius 0.83 cm in a magnetic field of 0.25 (Wb//m^2) . The de-Broglie wavelength associated with it will be-

A alpha -parhticle moves in a circular path of radius 0.83 cm in the presence of a magnetic field of 0.25 Wb//m^(2) . The de-Broglie wavelength assocaiated with the particle will be

A alpha -parhticle moves in a circular path of radius 0.83 cm in the presence of a magnetic field of 0.25 Wb//m^(2) . The de-Broglie wavelength assocaiated with the particle will be

A alpha -parhticle moves in a circular path of radius 0.83 cm in the presence of a magnetic field of 0.25 Wb//m^(2) . The de-Broglie wavelength assocaiated with the particle will be

A alpha -parhticle moves in a circular path of radius 0.83 cm in the presence of a magnetic field of 0.25 Wb//m^(2) . The de-Broglie wavelength assocaiated with the particle will be