" 10."x=log_(e)t+sin t,y=e^(t)+cos t

Find dy/dx : x = log t+ sin t, y = e^t +cos t

If x = e ^(t ) sin t, y = e ^(t) cos t, then (d ^(2) y )/(dx ^(2)) at t = pi is

Equations of the tangent and normal to the curve x=e^(t) sin t, y=e^(t) cos t at the point t=0 on it are respectively

If x = e^(t) sin t and y = e^(t) cos t, t is a parameter , then the value of (d^(2) x)/( dy^(2)) + (d^(2) y)/(dx^(2)) at t = 0 , is :

If x=e^t sin t , y=e^t cos t , t is a parameter , then (d^2y)/(dx^2) at (1,1) is equal to

If x=e^t sin t , y=e^t cos t , t is a parameter , then (d^2y)/(dx^2) at (1,1) is equal to

If x=e^(t)sin t,y=e^(t)cos t then (d^(2)y)/(dx^(2)) at x=pi is