`5^(2)times25^(3)times625=(5)^(?)`

((5^(3))^(-2)times(5^(2))^(-3)times(6)^(5))/((2)^(3)times(3)^(2)times(5)^(5))

[8^(-2/3)times2^(1/2)times25^(-5/4)]÷[32^(-2/5)times125^(-5/6)] =sqrt2

solve it : (ii) (-3)/(5)times(-3)/(5)times(-3)/(5)times(-3)/(5) (iii) (-9)/(2)times(4)/(2)times(-4)/(2)times(-4)/(2)times(-4)/(2)times(-4)/(2) (iv) (-5)/(3)times(-5)/(3)times(-5)/(3)times(-5)/(3) (v) (-6)/(2)times(-6)/(2)times(-6)/(2)times(-6)/(2)times(-6)/(2)

Simplify (3^(-5)times5^(-7)times(-2)^(3))/(3^(4)times5^(-2)times(-2)^(-3))

Find the product. a. (2)/(7)times(3)/(5) d. (5)/(6)times(12)/(11)times(22)/(25)

(1) (4)/((216)^((2)/(3)))+(1)/((256)^((3)/(4)))+(2)/((243)^((1)/(5))) (ii) ((64)/(125))^((2)/(3))+((256)/(625))^((1)/(4))+((3)/(7))^(0) (iii) ((81)/(16))^((3)/(4))(((25)/(9))^((3)/(2))-:((5)/(2))^(-3)) (iv) ((25)^((5)/(2))times(729)^((1)/(3)))/((125)^((2)/(3))times(27)^((2)/(3))times8^((4)/(3)))

((2)/(3))^(4)times((3)/(2))^(5)times((5)/(3))^(-2)times((3)/(5))^(-3)

Is [(-5)times2)]times3 = (-5)times[(2times3)] ?

Evaluate: a. (12 times (-15) times (24))/((-3) times 5) b. 90 times (-4) +405 div [110-{25-(25 times2)}]

Solve : (2/3)^4 times ( 3/2 )^5 times (5/3 )^-2 times ( 3/5 )^-3