The line `x+3y=0` is a diameter of the circle `x^2+y^2-6x+2y=0`

If the line x+2by+7=0 is a diameter of the circle x^(2)+y^(2)-6x+2y=0, then find the value of b

If the line x + 2by + 7 = 0 is a diameter of the circle x^(2) + y^(2) - 6x + 2y = 0 , then : b =

Which of the following line is a diameter of the circel x ^(2) + y^(2) -6x-8y-9=0 ?

Find the diameter of the circle 2x^(2)+2y^(2)-6x-9=0 .

The equation of a diameter of circle x ^(2) + y^(2)-6x + 2y =0, passing through origin is

If line 2x - y + k = 0 is a diameter of circle x^(2) + y^(2) + 6x - 6y + 5 = 0 , then k =

If (1,2)(2,a) are extremities of a diameter of the circle x^(2)+y^(2)-3x-4y+6=0 then a=

If one end of a diameter of the circle 3x^(2)+3y^(2)-9x+6y+5=0 is (1,2), then the other end is

The equation of the diameter of the circle 3(x^(2)+y^(2))-2x+6x-9-0 which is perpendicular to the line 2x+3y=12 is