No tangent can be drawn from the point `(5/2,1)` to the circumcircle of the triangle with vertices `(1,sqrt(3)),(1,-sqrt(3)),(3,-sqrt(3))` .

The incetre of the triangle with vertices (1,sqrt(3)),(0,0) and (2,0) is

Inradius of the triangle with vertices (1,1), (-1,-1), (-sqrt3, sqrt3) is

The incentre of a triangle with vertices (7,1),(-1,5) and (3+2sqrt(3),3+4sqrt(3)) is

The incentre of triangle with vertices (1, sqrt(3)), (0,0) and (2, 0) is

The area of triangle with vertices (sqrt(3)+i)z,(-3+sqrt(3)i)z and (sqrt(3)-3+(sqrt(3)+1)i)z is 48 then |z|=

A triangle is inscribed in a circle.The vertices of the triangle divide the circle into three arcs of length 3,4 and 5 ,then the area of the triangle is equal to 1.(9sqrt(3)(1+sqrt(3)))/(pi^(2)) 2.(9sqrt(3)(sqrt(3)-1))/(pi^(2)) 3.(9sqrt(3)(1+sqrt(3)))/(2 pi^(2)) 4.(9sqrt(3)(sqrt(3)-1))/(2 pi^(2))

Tangents drawn from (2, 0) to the circle x^2 + y^2 = 1 touch the circle at A and B . Then (A) A-= (1/2, sqrt(3)/2) , B -= (-1/2, - sqrt(3)/2) (B) A-= (- 1/2, (-sqrt(3)/2) , B -= (1/2, sqrt(3)/2) (C) A-= (1/2, sqrt(3)/2) , B-= (1/2, - sqrt(3)/2) (D) A-= (1/2, - sqrt(3)/2), B-= (1/2, sqrt(3)/2)

If the vertices of a triangle are (sqrt(5),0) ,sqrt(3),sqrt(2)), and (2,1), then the orthocentre of the triangle is (sqrt(5),0) (b) (0,0)(sqrt(5)+sqrt(3)+2,sqrt(2)+1)( d) none of these