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If alpha , beta, gamma are the length...

If `alpha , beta, gamma` are the lengths of the tangents from the vertices of a triangle to its incircle. Then

A

`alpha + beta + gamma = (1)/(r^(2))(alphabetagamma)`

B

`(1)/(alpha)+(1)/(beta) +(1)/(gamma) = r (alphabeta gamma)`

C

`alpha + beta + gamma = (1)/(r) (alpha beta gamma)`

D

`alpha^(2) + beta^(2) + gamma^(2) = (2)/(r) (alpha beta gamma)`

Text Solution

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The correct Answer is:
A
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