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The equation to the circle whose radius ...

The equation to the circle whose radius is 3 and which touches internally the circle `x^(2)+y^(2)-4x+6y-12=0" at this point (-1,1) is"`

A

`5x^2+5y^2+9x-6y-7=0`

B

`5x^2+5y^2-8x-14y-32=0`

C

`5x^2+5y^2-6x+8y-8=0`

D

`5x^2+5y^2+6x-8y-12=0`

Text Solution

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The correct Answer is:
B
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TS EAMCET PREVIOUS YEAR PAPERS-AP EAMCET ENGINEERING ENTRANCE EXAM ONLINE QUESTION PAPER 2019 (SOLVED)-MATHEMATICS
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