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The locus of the points of intersection of perpendicular normals of the parabola `y^2=4ax` is

A

`y^2-2ax+a^2=0`

B

`y^2-ax+2a^2=0`

C

`y^2-ax+2a^2=0`

D

`y^2-ax+3a^2=0`

Text Solution

Verified by Experts

The correct Answer is:
D
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