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If f(x) = a log |x| + bx^(2) + x has ext...

If f(x) = a log |x| + `bx^(2)` + x has extreme values at x = -1 and x = 2 , then the ordered pair (a,b) =

A

(2, -1)

B

`(2 ,- (1)/(2))`

C

`(-1, 2)`

D

`(- (1)/(2) , 2)`

Text Solution

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The correct Answer is:
B
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