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The equation of the circle which passes through the point (3, 2) bisects the circumference of the circle `x^(2)+y^(2)=15` and cuts the circle `x^(2)+y^(2)+4x+6y+3=0` orthogonally is

A

`x^(2)+y^(2)+6x+8y-43=0`

B

`x^(2)+y^(2)+6x-8y-15=0`

C

`x^(2)+y^(2)-6x+8y-11=0`

D

`x^(2)+y^(2)-6x-8y+21=0`

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The correct Answer is:
B
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