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If the normals drawn to the hyperbola xy...

If the normals drawn to the hyperbola xy = 4 at `(alpha_(i), beta_(i)) (i = 1,2,3,4)` are concurrent at the point (a, b), then
`((alpha_(1) + alpha_(2) + alpha_(3) + alpha_(4)))/((beta_(1) + beta_(2) + beta_(3) + beta_(4)))(alpha_(1)alpha_(2)alpha_(3)alpha_(4)) =`

A

`(-16b)/(a)`

B

`(-16a)/(b)`

C

`(4b)/(a)`

D

`(4a)/(b)`

Text Solution

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The correct Answer is:
B
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