A body is projected vertically from the surface of the earth of radius 'R' with a velocity equal t half of the escape velocity . The maximum heign reached by the body is

Options

A. `(R)/(2)`
B. `(R)/(3)`
C. `(R)/(4)`
D. `(R)/(5)`

Answer

B

Explanation

As, `v=Kv_(e)(K<1)` then
where, v=velocity of projection and `v_(e)`=escape velocity
The maximum height reached by the body is
`h=(RK^2)/(1-K^2)=(R((1)/(4)))/((1-(1)/(4)))=(R)/(4)xx(4)/(3)=(R)/(3)Rightarrowh=(R)/(3)`