A particle of mass m=5 units is moving with uniform speed `V=3sqrt2` units in the XY plane along the line Y = X + 4. The magnitude of the angular momentum about origin is,

Options

A. zero
B. 60 units
C. 7.5 units
D. 40 units

Answer

B

Explanation

The angular momentum, `L=mvb costheta`
where, m=mass of particle, v=velocity of particle b=position of particle with respect to origin and `theta`=angle between momentum vector and position vector.
`=5xx3sqrt(2)xx4xxcos45^(@)`
L=60 units