The ratio of energies of emtiied radiation by a black body at 600 K and 900 K when the surrounding temperature is 300, is

Options

A. `(5)/(16)`
B. `(7)/(16)`
C. `(3)/(16)`
D. `(9)/(16)`

Answer

C

Explanation

The ratio to energy, `(E_1)/(E_2)=(T_(1)^(4)-T_(s)^(4))/(T_(2)^(4)-T_(s)^(4))`
where, `T_(1),T_(s) "and" T_(2)` are the temperatures
`Rightarrow(E_1)/(E_2)=((600)^(4)-(300)^(4))/((900)^(4)-(300)^(4))=(3)/(16)`