In a region of uniform electric field ofn intencity E, an electron of mass `m_e` is released from rest. The distance travelled by the eloctron in a time t is

Options

A. `(2m_(e)t^(2))/(e)`
B. `(eEt^(2))/(2m_(e))`
C. `(m_(e)"gt"^(2))/(eE)`
D. `(2Et^(2))/(em_(e))`

Answer

B

Explanation

The force on electron in the electric field F=eE
`therefore "Acceleration",a=(F)/(m_e)=(eE)/(m_e)`
Now, from equation of motion, `S=(1)/(2)at^(2)=(1)/(2)(eE)/(m_e)t^(2)`
where, t=time