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A material of 0.25 cm^(2) cross sectiona...

A material of `0.25 cm^(2)` cross sectional area is placed in a magnetic field of strength (H) `1000 Am^(-1)`. Then the magnetic flux produced is (Susceptibility of material is 313)(Permeability of free space,`mu=4pixx10^(-7)Hm^(-1)`

A

`8.33xx10^(-8)Wb`

B

`1.84xx10^(-6)Wb`

C

`9.87xx10^(-6)Wb`

D

`3.16xx10^(-6)Wb`

Text Solution

Verified by Experts

The correct Answer is:
C
As, we know that
`Rightarrow mu=mu_(0)(1+x_(m))`
Now, the magnetic flux `phi=BA=muHA`
`=mu_(0)(1+x)HA`
`=4pixx10^(-7)(1+313)xx1000xx0.25xx10^(-4)`
`=9.87xx10^(-6)Wb`
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