In a Ac circuit aV and I are given below , then find the power dissiapted in the circuit
V= 50 sin (50t) V
` I=50 sin (50+(pi/3))mA `

Options

A. 0.625 W
B. 1.25 W
C. 2.50 W
D. 5.0 W

Answer

A

Explanation

As we know that, the power dissipated in an AC circuit is `P=(E_(0)i_(0)cosphi)/(2)`
Here, `E_(0)=50V, i_(0)=50ma=50xx10^(-3)A "and" phi=(pi)/(3) (i.e. cos""(pi)/(3)=(1)/(2))`
`therefore P=(50xx50xx10^(-3)xx1)/(2xx2)=0.625W`