The maximum amplitude of an amplitude modulated wave is 16 V, while the minimum amplitude is 4 V. The modulation index is

Options

A. 0.4
B. 0.5
C. 0.6
D. 4

Answer

C

Explanation

The modulation index in amplitude modulation is `In=(A_m)/(A_c)=(E_"max"-E_"min")/(E_"max"+E_"min")`
Given that, `E_("max")=16V "and" E_("min")=4V`
`Rightarrowm=(16-4)/(16+4)=(12)/(20)=(3)/(5)=0.6`