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Two bodies of masses 4m and 9m are seper...

Two bodies of masses 4m and 9m are seperated by distance 'r' . The gravitational potential at a point on this line joining them where the gravitational field becomes zero is

A

`(-25 Gm)/(r)`

B

`(-4Gm)/(r)`

C

`(-9 Gm)/(r)`

D

`(-13 Gm)/(r)`

Text Solution

Verified by Experts

The correct Answer is:
A

Atb the position when the gravitational field is zero. (Distance x is measured from 4 m mass)
`(G(4m))/(x) = (G(9m))/((r-x))`
`(4)/(x) =(9)/(r-x)`
4(r - x) = 9x
4r - 4x = 9x
4r = 9x + 4x
4r = 13 x
`x = (4)/(13) r`
The point p is at a distance `(4)/(13) r` from mass 4m and `(h - (4)/(13)r) =(9r)/(13) ` from mass m
` v = - (G(4m))/(((4)/(13)r)) -(G(9m))/((9r)/(13)) `
` v = - (26 Gm)/(r)`
Option (a) is nearest but none of the option is matching .
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