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An electron accelerated through a potent...

An electron accelerated through a potential difference V, passes through a uniform transverse magnetic field and experiences a force F. if the accelerating potential is increased to 2V, the electron in the same magnetic field will experience a force .

A

F

B

`(F)/(2)`

C

`sqrt(2)`F

D

2F

Text Solution

Verified by Experts

The correct Answer is:
C
`therefore` Magnetic force, F = q( V`xx ` B)
= qv B sin `theta`
For uniform transverse magnetic field , `theta = 90^(@)`
So, `" " F = qv B = q (sqrt((2qV)/(m_(e ))) ) B`
When electron accelerated through a potential difference,
`F = e (sqrt((2e(2V))/(m_(e ))) )" " `.... (i)
When electron accelerated through a potential difference 2V.
F. = e `(sqrt((2e(2V))/(m_(e ))) )`
From Eqs. (i) we get F. = `sqrt(2)` F
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