A block of mass 48 kg kept on a smooth horizontal surface is pulled by a rope of length 4 m by a horizontal force of 25 N applied to the other end. If the linear density of the rope is `0 . 5 kg m^(-3)` , the force acting on the block is

Options

A. 24 N
B. 25 N
C. 12 N
D. 13 N

Answer

A

Explanation

According to the question,
Given , linear density of rope, `lambda = 0 . 5 kgm^(3)`
Hence, mass of rope , `m = lambda * l`
`= 0. 5 xx 4 = 2kg`
Therefore, the total mass of system
`m = 48 + 2 = 50 kg`
`:.` Acceleration , `a = (F)/(M) = (25)/(50) = (1)/(2) ms^(-2)`
Hence, the force acting on the block is,
`F = 48 xx (1)/(2) = 24 N`