A Young 's double slit experimental setup is immersed in water of refrective index 1.33 . It has slit seperation 1 mm and the distance between slits and screen is 1.33 m . If the wavelength of incident light on slits is 6300 `Å` , then the fringe width on the screen is

Options

A. 6 . 3 m m
B. 0 . 63 m m
C. 0 . 63 m
D. 6 . 3 m

Answer

B

Explanation

When Young.s double slit experiment setup is immersed in water then fringe width , `y = (lambda D)/(mu d)`
Given, wavelength of incident lingt on slits , `lambda = 6300 Å = 63 00 xx 10^(-16) m `
distance between slit and screen , D = 1.33m and refractive index of water , `mu = 1.33`
Hence, the fringe width on the screen,
` y = (6300xx 10^(-10)xx 1.33)/(1.33 xx 1xx 10^(-3))`
`y = 6 . 3 xx 10^(-4) m `
`= 0 . 63 m m `