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The amplitude of the electric field in a...

The amplitude of the electric field in a parallel beam of plane electromagnetic waves of intensity 53.1 W `m^(-1)` is
(Permittivity of free space `= 8 . 85 xx 10 ^(-12) C^(2) N^(-1) M^(-2)` )

A

`400 NC^(-1)`

B

`50 NC^(-1)`

C

`100 NC^(-1)`

D

`200 NC^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
D

Given ,
intensity of electromagneitc wave , I = 531 W`m^(-2)`
Premittivity of free space,
`epsilon_(0) = 8 . 85 xx 10 ^(-12) C^(2) N^(-1) M^(-2)`
Intensity of electromagnetic wave, `I = (1)/(2)epsilon_(0) E _(0) ^(2) c`
where , `E_(0)` = amplitude of the electric field. `E(0) = sqrt((2I)/(in_(0) c)) = sqrt((2 xx 53.1)/(8.85 xx 10^(-12) xx 3 xx 10 ^(8)))`
`E_(0) = 200 NC^(-1)`
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