If the binding energy of `N^(14)` is 7 . 5 Mev per nucleons and that of `N^(15)` is 7 . 7 MeV per nucleon, then, the energy is required to remove a neutron from `N^(15)` is

Options

A. `5 . 25 MeV`
B. 0 . 2 MeV
C. 10 . 5 MeV
D. 0 . 4 MeV

Answer

C

Explanation

Given , binding energy per nucleon of `N^(14) = 7 . 5 ` Me V/nucleon
Binding energy per nucleon of
`N^(15) = 7 . 7 ` meV/nucleon
`:.` Total BE of `N^(14) = 7 . 5 xx 14 meV`
Total BE of `N^(15) = 7 . 7 xx 15 meV`
Then the energy requred to remove a neutron from `N^(15)`
`= BE _("total") N^(15) - BE_("total") N^(14)`
`= (7 . 7 xx 15 - 7 . 5 xx 14) MeV = 10 . 5 Me V`