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In a plance electromagnetic wave, the el...

In a plance electromagnetic wave, the electric field oscillates with a frequency `2xx10^(10) s^(-1)` and amplitude `40 Vm^(-1)`, then the energy density due to electric field is `(epsilon_(0)=8.85xx10^(-12)Fm^(-1))`

A

`1.52xx10^(9)" Jm"^(-3)`

B

`2.54xx10^(9)" Jm"^(-3)`

C

`3.54xx10^(9)" Jm"^(-3)`

D

`4.56xx10^(9)" Jm"^(-3)`

Text Solution

Verified by Experts

The correct Answer is:
C

Energy density due to electric field is
`U=(1)/(2) epsi_(0) E^(2)`
Here, `E=(E_(0))/(sqrt(2))=(40)/(sqrt(2))`
`therefore" "U=(1)/(2)xx8.85xx10^(-12) xx (40xx40)/(2)`
`=3.54xx10^(-9) J//m^(3)`
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