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If 200 MeV of energy is released in the ...

If 200 MeV of energy is released in the fission of one nucleus of `""^(236)_(92)U`, the number of nuclei that must undergo fission to release an energy of 1000 J is,

A

`3.125xx10^(13)`

B

`6.25xx10^(13)`

C

`12.5xx10^(13)`

D

`3.125xx10^(14)`

Text Solution

Verified by Experts

The correct Answer is:
A
Number of nuclei `=(E_("total"))/(E_(1))=(1000 J)/(200 Me V)`
`=(1000 J)/(200xx10^(6) xx1.6xx10^(-19) J)`
`rArr" "N=(10^(4))/(3.2)`
`rArr" "N=3.125 xx 10^(13)`
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