The electric field due to a short electric dipole at a distance r on the axial line from its mid-point is 2r on the equatorial line from the mid -point of dipole. Then the value of x is

Options

A. 16
B. 9
C. 25
D. 36

Answer

A

Explanation

On axis , field magnitude , `E_1 = (2 kp)/(r^3)`
On equatorial axis, field magnitude `E_(2) = (kp)/(2r)^3 = (kp)/(8r^3)`
So, `E_(1)=16 E_(2) rArr x = 16`