A system containing masses and pulleys connected on an inclined plane is shown in the figure If the system is in equilibrium then the value of m is

Options

A. 1 kg
B. 0.5 kg
C. 0.75 kg
D. 0.25 kg

Answer

B

Explanation

(b) According to the question - the complete situations is shown in the following figure

Since system is in equilibrium hence
`T= mg `
T= (2 g - `T_(1)`) sin `30^(@)`
`T_(1) = 1g`
From Eqs . (ii) and (iii) we get
`T = (2g -1 g) sin 30^(@) = g sin 30^(@)`
`T= (g )/(2)`
`:. ` From Eqs. (i ) and (iV ) we get
`mg = (g )/(2)`
`rArr m= 0.5 kg`