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A particle of mass 15 kg is moving with ...

A particle of mass 15 kg is moving with a uniform speed `8ms^(-1)` in xy-plane along the line 3y = 4x + 10, then the magnitude of its angular momentum about the origin in
`kg-m^(2)s^(-1)" is "...(sin53^(@)=4/5)`

A

240

B

80

C

120

D

280

Text Solution

Verified by Experts

The correct Answer is:
A

Angular momentum = `mvr_(1)`
= `15xx8xx(10/sqrt(3^(2)+4^(2)))=15xx8xx2=240kg-m^(2)s^(-1)`
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