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A graph drawn between absolute temperatu...

A graph drawn between absolute temperature and volume of 3 moles of helium gas as shown in the figure. If 5 cal of heat is used in the process, then the work done is

A

21.0 J

B

8.4 J

C

12.6 J

D

6.2 J

Text Solution

Verified by Experts

The correct Answer is:
B
In given graph,
`VpropTrArrV/T` = constant
Hence, process is a constant pressure process.
So, `DeltaQ=nC_(p)DeltaT andDeltaW=pDeltaV=nRDeltaT=nR*(DeltaQ)/(nC_(p))`
= `(DeltaQR)/(5/2R)=2/5xxDeltaQ=2"cal"=2xx4.2J=8.4J`
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