A straight conductor of length 32 cm carries a current of 30 A. Magnetic induction at a point in air at a perpendicular distance of 12 cm from the mid-point of the conductor is

Options

A. 0.2 G
B. 0.3 G
C. 0.4 G
D. 0.5 G

Answer

C

Explanation

`beta=(mu_(0)I)/(4pir)(sintheta_(1)+sintheta_(2))`
= `(10^(-7)xx30)/(12xx10^(-2))(2xx16/20)`
= `4xx10^(-5)T`
= `0.4xx10^(-4)T`
= 0.4 G