In the common-base configuration, a transistor has current amplification factor 0.95. If the transistor is used in common-emitter configuration and base current changes by `2muA`, then the change in the collector current is

Options

A. `19muA`
B. `0.91muA`
C. `1.9muA`
D. `38muA`

Answer

D

Explanation

Given, `alpha=0.95`
So, `beta=alpha/(1-alpha)=0.95/(1-0.95)=19`
= `beta=(DeltaI_(C))/(DeltaI_(B))=19`
or `DeltaI_(C)=19xx2=38muA`