The motion of a particle along a straight line is described by the function x = `(2t-3)^(2)` where x is in metres and t is in seconds . The acceleration of the particle at =2s is

Options

A. 1`ms^(-2)`
B. `4 ms^(-2)`
C. `8 ms^(-2)`
D. `7 ms^(-2)`

Answer

C

Explanation

Given x= `(2t-3)^(2)`
where x= displacement and t = time .
Differentiate w.r.t. time we get Velocity `v=(dx)/(dt) = 8t-12 `
Acceleration `a=(dv)/(dt)=8 m//s^(2)`