One end of a light string is fixed to a clamp on the ground and the other end passes over a fixed frictionless pulley as shown in the figure. It makes an angle of `30^(@)` with the ground . The clamp can tolerate a vertical force of 40 N . If a monkey of mass 5 kg were to climb up the rope then the maximum acceleration in the upward direction with which it can climb safely is (g=10 `ms^(-2))`

Options

A. `2 ms^(-2)`
B. `4 ms^(-2)`
C. `6 ms^(-2)`
D. `8 ms^(-2)`

Answer

C

Explanation

Let T is tension in the string.
Maximum vertical force on clamp T sin `30^(@)= 40`
`implies T.(1)/(2)= 40`
`implies T = 80 N`
Let maximum acceleration of monkey for state climbing is a. Then FBD of monkey

T -mg=ma`implies a = (T-mg)/(m)`
`a=(80-5xx10)/(5)`
`a=6m//s^(2)`