In the given circuit current `I` is independent of the resistance `R_(6)` . Then

Options

A. `R_(1) R_(2) R_(5)= R_(3)R_(4) R_(6)`
B. `(1)/(R_(5))+ (1)/(R_(6))=(1)/(R_(1)+R_(2))+(1)/(R_(3)+R_(4))`
C. `R_(1)R_(4)=R_(2)R_(3)`
D. `R_(1)R_(3)=R_(2)R_(4)`

Answer

C

Explanation

If resistance `R_(1), R_(2), R_(3), R_(4)` and `R_(6)` from Wheatstone brige then current will independent of resistance of `R_(6)`.
For this `(R_(1))/( R_(2))` = `(R _(3))/(R_(4)) implies R_(1)R_(4)= R_(2)R_(3)`