The Lewis structure for `O_(3)` molecule is given below. The correct formal charges on oxygen atoms labelled 1, 2, 3 are respectively.

Options

A. `- 1, 0 , + 1`
B. `+ 1 , 0, -1`
C. `+ 1, -1,0`
D. `0, +1, -1`

Answer

A

Explanation

`:.` Formal charge = number of valency electron = [(number of lp `+(1)/(2)` number of bp of electron]
`{:(lp = "lone pair of electrons"),(bp="bond pair of electrons"):}}`
`:.` for
F . C for `O_((1))` = 6 - [6 + 1] = - 1
F . C for `O_((2))` = 6 - [4 +2] = 0
F . C for `O_((3))` = 6 - [2 + 3] = + 1