The changes in bond length with respect to N - N and O - O , when `N_(2)` becomes `N_(2)^(+)` and `O_(2)` becomes `O_(2)^(+)` are respectively

Options

A. increases, decreases
B. decreases, increases
C. increases, increases
D. decreases, decreases

Answer

A

Explanation

` N_(2) (14) rarr sigma 1 s^(2) lt sigma1 s^(2) lt sigma 2 s^(2) lt sigma 2s^(2) lt pi 2p_(x)^(2) approx pi 2p_(y)^(2) lt sigma 2p_(z)^(2)`
bond order = `(10 - 4)/(2) = 3 `
`N_(2)^(+) (13) rarr sigma 1 s^(2) lt sigma 2 s^(2) lt sigma 2s^(2) lt pi 2p_(x)^(2) approx pi 2p_(y)^(2) lt sigma 2p^(1)`.
Bond order = `( 9 - 4)/(2) = 2.5 `
`O_(2)(16) rarr sigma 1 s^(2) lt sigma 2 s^(2) lt sigma 2s^(2) lt sigma 2p_(z)^(2) lt pi 2p_(x)^(2) approx pi 2p_(y)^(2) lt sigma 2p_(x)^(1) approx pi 2p_(y)^(1)`
Bond order = `(10 - 6)/(2) = 2 `
` O_(2)^(+) (15) rarr sigma 1 s^(2) lt sigma 2 s^(2) lt sigma 2s^(2) lt sigma 2p_(z)^(2) lt pi 2p_(x)^(2) = pi 2p_(y)^(2) lt sigma 2p_(x)^(1) = pi 2p_(y)^(0)`
bond order = `(10 - 5)/(2) = 25 `
`therefore` Bond order `prop (1)/("Bond length")`
`therefore` In case of `N_(2)^(+)` bond length increases as bond order decreases. While in `O_(2)^(+)` bond order increases and hence bond length decreases.