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Observe the following equations NH(3) ...

Observe the following equations
`NH_(3) + Ag^(+) hArr (Ag (NH_(3)) ]^(+) , " " K_(1) = 1.6 xx 10^(3)`
`[ Ag(NH_(3) ]^(+) + NH_(3) hArr [ Ag (NH_(3))_(2) ]^(+), K_(2) = 6.8 xx 10^(3)`
the equilibrium constant for the following reaction, `Ag^(+) + 2NH_(3) hArr [ Ag (NH_(3))_(2) ]^(+)` is

A

`6.008 xx 10^(3)`

B

`1.088 xx 10^(7)`

C

`1.088 xx 10^(8)`

D

`1.028 xx 10^(3)`

Text Solution

Verified by Experts

The correct Answer is:
B
When silver ion reacts with `NH_(3)`, then diammine silver (I) ion is formed.
`Ag^(+) + NH_(3) harr [ Ag (NH_(3) ]^(+), K_(1) = 1.6 xx 10^(3)` … (i)
`[ Ag(NH_(3)) ]^(+) + NH_(3) harr [ Ag (NH_(3) )_(2) ]^(+)`
`K_(2) = 6.8 xx 10^(3) " " ` (ii)
The equilibrium constant for the following reaction,
`Ag^(+) + 2.NH_(3) harr [Ag (NH_(3))_(2) ]^(+) , K_(3) = ? " " ` ... (iii)
Here, ` " " K_(3) = K_(1) xx K_(2)`
`K_(3) = 1.6 xx 10^(3) xx 6.8 xx 10^(3)`
` = 1.088 xx 10^(7)`
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