Dissolving 120 g of a compound (mol. Wt =60) in 1000 g of water gave a solution of density `1.12 g mL^(-1)`. The molarity of solution is

Options

A. 1.0 M
B. 2.0 M
C. 2.5 M
D. 4.0 M

Answer

B

Explanation

Given, density `(d) =1.12g mL^(-1)`
Mass of solute (w) =120 g
Molar mass of solute (M)=60
Mass of solvent (w) =1000 g =1000 mL
`therefore` Total mass =1000+120=1120 g
`because" "d=(Mass)/("Volume (V)")`
`therefore` Total volume `(V) =(1120)/(1.12) =1000 mL`
`because" Molarity "(c)=(w)/(M) xx(1000)/(V)`
`therefore` Molarity `(c) =(w)/(m) xx(1000)/(1000)=(120)/(60) =2.0 m`